Product Law of Logs
loga(m*n) = logam + logan
if a>0, so m>0,
for example:
let m = ax
logam = x
and if n>0, then a≠1
let n = ay
logam = x
and if n>0, then a≠1
let n = ay
logan = y
that would mean...
m*n = ax * ay
m*n = ax + y
m*n = ax + y
loga(m*n) = x+y
therefore:
the new proven product law!
therefore:
the new proven product law!
loga(m*n) = logam + logan
For Example:
log64+ log654
if the law applied then it would mean...
log64+ log654 = log6(4*54)
log64+ log654 = log6(216)
6x = 216
6x = 63
x = 3
therefore:
log64+ log654 = log6(216) = 3
Quotient Law of Logs:
loga(m/n) = logam - logan
log64+ log654
if the law applied then it would mean...
log64+ log654 = log6(4*54)
log64+ log654 = log6(216)
6x = 216
6x = 63
x = 3
therefore:
log64+ log654 = log6(216) = 3
Quotient Law of Logs:
loga(m/n) = logam - logan
so if a>0, then m>0
let m = ax
For example:
log5375-log515
if the law applied, that would mean:
log5375-log515 = log5(375/15)
log5375-log515 = log5(25)
5x = 25
5x = 52
let m = ax
logam = x
if n>0, a≠1
let n = aylogan = y
now...
now...
m / n = ax / ay
m / n = ax-y
m / n = ax-y
loga (m / n) = x - y
therefore our new proven quotient law is:
therefore our new proven quotient law is:
loga(m / n) = logam - logan
For example:
log5375-log515
if the law applied, that would mean:
log5375-log515 = log5(375/15)
log5375-log515 = log5(25)
5x = 25
5x = 52
x = 2
that would mean
log5375-log515 = log5(25) = 2
that would mean
log5375-log515 = log5(25) = 2
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