Wednesday, September 23, 2009

Per4: Usain Bolt's 2008 Race Analysis


Today in class, we examined the concept of an average rate of change by analyzing different intervals of Usain Bolt's 100m World Record run at the 2008 Beijing Olympics. We used data from the article, "Bolt's 9.69s. Analysis of speed during the world record. How fast did Bolt run?"

Please add a comment regarding the race interval that your group was responsible for. Include the calculation that you used to determine the average velocity. This may be a good opportunity to try out the sitmo link on the right-hand side of the blog.)

(You can view the video in the post below.)
Posted by at
Labels: , , ,

21 comments:

  1. cassbulandresSeptember 23, 2009 at 4:01 PM

    Interval: 10m - 20m
    Distance Travelled: 10m
    Time Elapsed: 2.87s - 1.85s = 1.02s

    V = d2 - d1/t2 - t1
    = 20 - 10/2.87 - 1.85
    = 9.8m/s

    ReplyDelete
  2. Stephanie TSeptember 23, 2009 at 4:33 PM

    INTERVAL : 20 - 30 m
    DISTANCE TRAVELLED : 10 m
    TIME ELAPSED : 0.91 s

    v = d2 - d1 / t2 - t1
    = 10m / 0.91s
    =(approximately) 11m/s

    ReplyDelete
  3. Jay CeeSeptember 23, 2009 at 4:48 PM

    Interval: 10 to 20 m
    Distance travelled: 10m
    Time elapsed: 1.02 sec

    V= d2-d1/t2-t1
    = (20-10)/(2.87-1.85)
    = (10m)/(1.02s)
    = 9.80 m/s

    ReplyDelete
  4. graceLSeptember 23, 2009 at 5:54 PM

    Interval: 80 to 90 m
    Distance traveled: 10m
    Time elapsed: 0.83s

    v = d2-d1/t2-t1
    = (90-80)/(8.79.-7.96)
    = (10m)/(0.83s)
    = 12.05 m/s

    ReplyDelete
  5. Lorraine W.September 23, 2009 at 5:55 PM

    Interval: 70-80m
    Distance Traveled: 80m-70m = 10m
    Time Elapsed: 7.96-7.14 = 0.82s

    Average Velocity = d2-d1/t2-t1
    = 10m/0.82s
    = 12.2m/s

    ReplyDelete
  6. kevin zSeptember 23, 2009 at 6:03 PM

    Interval: 30 to 40 m
    Distance traveled: 10m
    Time elapsed: 0.87s

    v = d2-d1/t2-t1
    = (40-30)/(4.65-3.78)
    = (10m)/(0.87s)
    = 11.49 m/s

    ReplyDelete
  7. Kelly CSeptember 23, 2009 at 6:13 PM

    Interval: 80 m to 90 m
    Distance travelled: 10 m

    Time at 90 m: 8.79 s
    Time at 80 m: 7.96 s
    Time elapsed: 0.83 s

    V = (delta d)/(delta t)
    V = 10m/0.83s
    V = 12.05 m/s

    ReplyDelete
  8. Nara SSeptember 23, 2009 at 6:30 PM

    Interval: 60 m to 70 m
    Distance Travelled: 70 m - 60 m = 10 m
    Time Elapsed: 7.14 s - 6.32 s = 0.82 s

    AV=delta d/ delta t
    =d2 - d1/t2 - t1
    =(70 m - 60 m)/(7.14 s - 6.32 s)
    =(10 m)/(0.82 s)
    =12.2 m/s

    ReplyDelete
  9. ShaniseASeptember 23, 2009 at 6:32 PM

    Interval: 70m to 80m
    Distance travelled: d2-d1=10m
    Time elasped: t2-t1= 7.14-6.32=0.82

    Average velocity=d2-d1/t2-t1
    =10/0.82
    =12.2m/s

    ReplyDelete
  10. Selvia G.September 23, 2009 at 7:27 PM

    Interval: 70-80m
    Distance Traveled: 80m-70m = 10m
    Time Elapsed: 7.96-7.14 = 0.82s

    Average Velocity = d2-d1/t2-t1
    = 10m/0.82s
    = 12.2m/s

    ReplyDelete
  11. David L.September 23, 2009 at 7:31 PM

    Interval: 50 to 60

    Distance Traveled:
    = d2-d1
    = 60m-50m
    = 10 m

    Time Elapsed: t2
    =t2-t1
    = 6.32s-5.5s
    = 0.82 s

    Average Velocity
    = d2-d1 / t2-t1
    = 10m/0.82s
    = 12.2m/s

    ReplyDelete
  12. Rachel.DSeptember 23, 2009 at 7:56 PM

    interval: 0m- 10m

    change in distance (m)= d2-d1
    = 10m-0m
    = 10m

    change in time (s)= t2-t1
    = 1.85s-0s
    = 1.85 seconds

    average velocity (m/s)= change in distance/change in time
    = 10m/1.85s
    = approximately 5.4 m/s

    ReplyDelete
  13. SabrinaDSeptember 23, 2009 at 8:39 PM

    Interval-> 0-10 m

    d= m t= s

    (t1, d1) = (0,0) (t2, d2) = (1.85, 10)

    AROC [0,10} = d2-d1
    t2-t1

    = 10m-0m
    1.85s-0s
    = approx. 5.4 m/s

    Therefore, Bolt's average velocity for the interval 0-10 m is 5.4m/s

    ReplyDelete
  14. Max M.September 23, 2009 at 9:12 PM

    Interval= 20m-30m
    t1= 2.87s
    t2= 3.78s
    d1= 20m
    d2= 30m

    =30-20/3.78-2.87
    =10/0.91
    =11m/s

    ReplyDelete
  15. Brenna FSeptember 23, 2009 at 9:18 PM

    This comment has been removed by the author.

    ReplyDelete
  16. Brenna FSeptember 23, 2009 at 9:19 PM

    Interval: 20m - 30m
    Distance Travelled: 10m
    Time Elapsed: 3.78s - 2.87s = 0.91 s

    Average Velocity = (d2 - d1) \ (t2 - t1)
    = 10m \ 0.91s
    = 11.0 m/s

    Therefore, the average velocity is approx. 11.0 m/s.

    ReplyDelete
  17. AdeeeeeeeSeptember 23, 2009 at 9:47 PM

    Interval: 40m-50m
    Distance Traveled: 10m
    Time Elapsed:
    = t2-t1
    = 5.5s-4.65s
    = 0.85s

    Average Velocity:
    = d2-d1 / t2-t1
    = 10m/0.85s
    = 11.8m/s

    ReplyDelete
  18. StephanieYSeptember 23, 2009 at 10:06 PM

    Interval: 90m-100m

    Distance Travelled: Δd = d2-d1
    = 100 m-90 m
    = 10 m

    Time Elapsed: Δt = t2-t1
    = 9.69 s-8.79 s
    = 0.9 s

    Average Velocity = Δd/Δt
    = 10 m/0.9 s
    = 11.1 m/s(rounded to the nearest tenth)

    .: The average velocity is approximately 11.1 m/s.

    ReplyDelete
  19. StephanieSSeptember 23, 2009 at 10:32 PM

    Interval (m) : 20 - 30 m
    Distance Travelled : d2-d1= 10 m
    Time Elapsed: t2-t1 = 0.91 s

    v = d2 - d1 / t2 - t1
    = 10m / 0.91s
    = 10.99m/s
    = 11m/s (approximately)

    .:. The average velocity is approximately 11m/s.

    ReplyDelete
  20. corradocSeptember 23, 2009 at 11:44 PM

    Interval(m) 30-40m
    Distance travelled: d2-d1= 10m
    Time Elapsed: t2-t1= 0.87s (rounded to the nearest hundreth)

    v=d2-d1/t2-t1
    =10m/0.87s
    =approximately 11.49m/s

    .:. the average velocity is approximately 11.49m/s

    ReplyDelete
  21. Heimdall.SSeptember 24, 2009 at 12:18 AM

    Interval(m):30 to 40
    Distance Traveled: d2-d1 = 10m
    Time ElapsedL t1-t2 = 0.87s

    v = d2 - d1 / t2 - t1
    = 10m / 0.87s
    = 11.5m/s
    = 11m/s (approximately)

    ReplyDelete

Note: Only a member of this blog may post a comment.

Subscribe to: Post Comments (Atom)