Wednesday, September 23, 2009

Per4: Usain Bolt's 2008 Race Analysis


Today in class, we examined the concept of an average rate of change by analyzing different intervals of Usain Bolt's 100m World Record run at the 2008 Beijing Olympics. We used data from the article, "Bolt's 9.69s. Analysis of speed during the world record. How fast did Bolt run?"

Please add a comment regarding the race interval that your group was responsible for. Include the calculation that you used to determine the average velocity. This may be a good opportunity to try out the sitmo link on the right-hand side of the blog.)

(You can view the video in the post below.)

21 comments:

  1. Interval: 10m - 20m
    Distance Travelled: 10m
    Time Elapsed: 2.87s - 1.85s = 1.02s

    V = d2 - d1/t2 - t1
    = 20 - 10/2.87 - 1.85
    = 9.8m/s

    ReplyDelete
  2. INTERVAL : 20 - 30 m
    DISTANCE TRAVELLED : 10 m
    TIME ELAPSED : 0.91 s

    v = d2 - d1 / t2 - t1
    = 10m / 0.91s
    =(approximately) 11m/s

    ReplyDelete
  3. Interval: 10 to 20 m
    Distance travelled: 10m
    Time elapsed: 1.02 sec

    V= d2-d1/t2-t1
    = (20-10)/(2.87-1.85)
    = (10m)/(1.02s)
    = 9.80 m/s

    ReplyDelete
  4. Interval: 80 to 90 m
    Distance traveled: 10m
    Time elapsed: 0.83s

    v = d2-d1/t2-t1
    = (90-80)/(8.79.-7.96)
    = (10m)/(0.83s)
    = 12.05 m/s

    ReplyDelete
  5. Interval: 70-80m
    Distance Traveled: 80m-70m = 10m
    Time Elapsed: 7.96-7.14 = 0.82s

    Average Velocity = d2-d1/t2-t1
    = 10m/0.82s
    = 12.2m/s

    ReplyDelete
  6. Interval: 30 to 40 m
    Distance traveled: 10m
    Time elapsed: 0.87s

    v = d2-d1/t2-t1
    = (40-30)/(4.65-3.78)
    = (10m)/(0.87s)
    = 11.49 m/s

    ReplyDelete
  7. Interval: 80 m to 90 m
    Distance travelled: 10 m

    Time at 90 m: 8.79 s
    Time at 80 m: 7.96 s
    Time elapsed: 0.83 s

    V = (delta d)/(delta t)
    V = 10m/0.83s
    V = 12.05 m/s

    ReplyDelete
  8. Interval: 60 m to 70 m
    Distance Travelled: 70 m - 60 m = 10 m
    Time Elapsed: 7.14 s - 6.32 s = 0.82 s

    AV=delta d/ delta t
    =d2 - d1/t2 - t1
    =(70 m - 60 m)/(7.14 s - 6.32 s)
    =(10 m)/(0.82 s)
    =12.2 m/s

    ReplyDelete
  9. Interval: 70m to 80m
    Distance travelled: d2-d1=10m
    Time elasped: t2-t1= 7.14-6.32=0.82

    Average velocity=d2-d1/t2-t1
    =10/0.82
    =12.2m/s

    ReplyDelete
  10. Interval: 70-80m
    Distance Traveled: 80m-70m = 10m
    Time Elapsed: 7.96-7.14 = 0.82s

    Average Velocity = d2-d1/t2-t1
    = 10m/0.82s
    = 12.2m/s

    ReplyDelete
  11. Interval: 50 to 60

    Distance Traveled:
    = d2-d1
    = 60m-50m
    = 10 m

    Time Elapsed: t2
    =t2-t1
    = 6.32s-5.5s
    = 0.82 s

    Average Velocity
    = d2-d1 / t2-t1
    = 10m/0.82s
    = 12.2m/s

    ReplyDelete
  12. interval: 0m- 10m

    change in distance (m)= d2-d1
    = 10m-0m
    = 10m

    change in time (s)= t2-t1
    = 1.85s-0s
    = 1.85 seconds

    average velocity (m/s)= change in distance/change in time
    = 10m/1.85s
    = approximately 5.4 m/s

    ReplyDelete
  13. Interval-> 0-10 m

    d= m t= s

    (t1, d1) = (0,0) (t2, d2) = (1.85, 10)

    AROC [0,10} = d2-d1
    t2-t1

    = 10m-0m
    1.85s-0s
    = approx. 5.4 m/s

    Therefore, Bolt's average velocity for the interval 0-10 m is 5.4m/s

    ReplyDelete
  14. Interval= 20m-30m
    t1= 2.87s
    t2= 3.78s
    d1= 20m
    d2= 30m

    =30-20/3.78-2.87
    =10/0.91
    =11m/s

    ReplyDelete
  15. This comment has been removed by the author.

    ReplyDelete
  16. Interval: 20m - 30m
    Distance Travelled: 10m
    Time Elapsed: 3.78s - 2.87s = 0.91 s

    Average Velocity = (d2 - d1) \ (t2 - t1)
    = 10m \ 0.91s
    = 11.0 m/s

    Therefore, the average velocity is approx. 11.0 m/s.

    ReplyDelete
  17. Interval: 40m-50m
    Distance Traveled: 10m
    Time Elapsed:
    = t2-t1
    = 5.5s-4.65s
    = 0.85s

    Average Velocity:
    = d2-d1 / t2-t1
    = 10m/0.85s
    = 11.8m/s

    ReplyDelete
  18. Interval: 90m-100m

    Distance Travelled: Δd = d2-d1
    = 100 m-90 m
    = 10 m

    Time Elapsed: Δt = t2-t1
    = 9.69 s-8.79 s
    = 0.9 s

    Average Velocity = Δd/Δt
    = 10 m/0.9 s
    = 11.1 m/s(rounded to the nearest tenth)

    .: The average velocity is approximately 11.1 m/s.

    ReplyDelete
  19. Interval (m) : 20 - 30 m
    Distance Travelled : d2-d1= 10 m
    Time Elapsed: t2-t1 = 0.91 s

    v = d2 - d1 / t2 - t1
    = 10m / 0.91s
    = 10.99m/s
    = 11m/s (approximately)

    .:. The average velocity is approximately 11m/s.

    ReplyDelete
  20. Interval(m) 30-40m
    Distance travelled: d2-d1= 10m
    Time Elapsed: t2-t1= 0.87s (rounded to the nearest hundreth)

    v=d2-d1/t2-t1
    =10m/0.87s
    =approximately 11.49m/s

    .:. the average velocity is approximately 11.49m/s

    ReplyDelete
  21. Interval(m):30 to 40
    Distance Traveled: d2-d1 = 10m
    Time ElapsedL t1-t2 = 0.87s

    v = d2 - d1 / t2 - t1
    = 10m / 0.87s
    = 11.5m/s
    = 11m/s (approximately)

    ReplyDelete

Note: Only a member of this blog may post a comment.